5,5x^2+50x+88=0

Solution for 5,5x^2+50x+88=0 equation:

5.5x^2+50x+88=0

a = 5.5; b = 50; c = +88;
Δ = b2-4ac
Δ = 502-4·5.5·88
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{141}}{2*5.5}=\frac{-50-2\sqrt{141}}{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{141}}{2*5.5}=\frac{-50+2\sqrt{141}}{11}
$